If \[5\tan \theta =4,\] then \[\frac{5\sin \theta -3\cos \theta }{5\sin \theta +2\cos \theta }=\] [Karnataka CET 1998]

If \[5\tan \theta =4,\] then \[\frac{5\sin \theta -3\cos \theta }{5\si

1.	If \[5\tan \theta =4,\] then \[\frac{5\sin \theta -3\cos \theta }{5\sin \theta +2\cos \theta }=\] [Karnataka CET 1998]
A.	0
B.	1
C.	44348
D.	6
Answer» D. 6

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If \[5\tan \theta =4,\] then \[\frac{5\sin \theta -3\cos \theta }{5\sin \theta +2\cos \theta }=\] [Karnataka CET 1998]

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