If \[3{{\sin }^{-1}}\frac{2x}{1-{{x}^{2}}}-4{{\cos }^{-1}}\frac{1-{{x}^{2}}}{1+{{x}^{2}}}+2{{\tan }^{-1}}\frac{2x}{1-{{x}^{2}}}=\frac{\pi }{3}\] then \[x\] =

If \[3{{\sin }^{-1}}\frac{2x}{1-{{x}^{2}}}-4{{\cos }^{-1}}\frac{1-{{x}

1.	If \[3{{\sin }^{-1}}\frac{2x}{1-{{x}^{2}}}-4{{\cos }^{-1}}\frac{1-{{x}^{2}}}{1+{{x}^{2}}}+2{{\tan }^{-1}}\frac{2x}{1-{{x}^{2}}}=\frac{\pi }{3}\] then \[x\] =
A.	\[\sqrt{3}\]
B.	\[\frac{1}{\sqrt{3}}\]
C.	1
D.	None of these
Answer» C. 1

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If \[3{{\sin }^{-1}}\frac{2x}{1-{{x}^{2}}}-4{{\cos }^{-1}}\frac{1-{{x}^{2}}}{1+{{x}^{2}}}+2{{\tan }^{-1}}\frac{2x}{1-{{x}^{2}}}=\frac{\pi }{3}\] then \[x\] =

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