If 2x - 5y = 7z - 3y then, for xyz ≠ 0, \(\frac {8x^3 - 343z^3 - 8 – McqOptions

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1.	If 2x - 5y = 7z - 3y then, for xyz ≠ 0, \(\frac {8x^3 - 343z^3 - 8y^3}{xyz} \)
A.	80
B.	82
C.	84
D.	86
Answer» D. 86

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