1.

If (2a 3)2 + (3b + 4)2 + (6c + 1)2 = 0, then the value of
a3 + b3 + c3 3ac
+ 3 is :
a2 + b2 + c2

A. abc + 3
B. 6
C. 0
D. 3
Answer» E.


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