If \(2^x = 3^y = 6^{-z}\) then \(\left(\dfrac{1}{x} + \dfrac{1}{y} – McqOptions

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1.	If \(2^x = 3^y = 6^{-z}\) then \(\left(\dfrac{1}{x} + \dfrac{1}{y} + \dfrac{1}{z}\right)\) is equal to
A.	0
B.	1
C.	\(\dfrac{3}{2}\)
D.	\(-\dfrac{1}{2}\)
Answer» B. 1

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