If \[{{2}^{x}}+{{2}^{y}}={{2}^{x+y}}\], then \[\frac{dy}{dx}=\] [MP PET 1995; AMU 2000]

\[\frac{{{2}^{x}}+{{2}^{y}}}{{{2}^{x}}-{{2}^{y}}}\]

\[{{2}^{x-y}}\frac{{{2}^{y}}-1}{{{2}^{x}}-1}\]

\[{{2}^{x-y}}\frac{{{2}^{y}}-1}{1-{{2}^{x}}}\]

If \[{{2}^{x}}+{{2}^{y}}={{2}^{x+y}}\], then \[\frac{dy}{dx}=\]

1.	If \[{{2}^{x}}+{{2}^{y}}={{2}^{x+y}}\], then \[\frac{dy}{dx}=\] [MP PET 1995; AMU 2000]
A.	\[{{2}^{x-y}}\frac{{{2}^{y}}-1}{{{2}^{x}}-1}\]
B.	\[{{2}^{x-y}}\frac{{{2}^{y}}-1}{1-{{2}^{x}}}\]
C.	\[\frac{{{2}^{x}}+{{2}^{y}}}{{{2}^{x}}-{{2}^{y}}}\]
D.	None of these
Answer» C. \[\frac{{{2}^{x}}+{{2}^{y}}}{{{2}^{x}}-{{2}^{y}}}\]

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If \[{{2}^{x}}+{{2}^{y}}={{2}^{x+y}}\], then \[\frac{dy}{dx}=\] [MP PET 1995; AMU 2000]

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