If \[{{(1+x)}^{n}}={{C}_{0}}+{{C}_{1}}x+{{C}_{2}}{{x}^{2}}+....+{{C}_{n}}{{x}^{n}},\]then \[{{C}_{0}}{{C}_{2}}+{{C}_{1}}{{C}_{3}}+{{C}_{2}}{{C}_{4}}+...+{{C}_{n-2}}{{C}_{n}}=\]

If \[{{(1+x)}^{n}}={{C}_{0}}+{{C}_{1}}x+{{C}_{2}}{{x}^{2}}+....+{{C}_{

1.	If \[{{(1+x)}^{n}}={{C}_{0}}+{{C}_{1}}x+{{C}_{2}}{{x}^{2}}+....+{{C}_{n}}{{x}^{n}},\]then \[{{C}_{0}}{{C}_{2}}+{{C}_{1}}{{C}_{3}}+{{C}_{2}}{{C}_{4}}+...+{{C}_{n-2}}{{C}_{n}}=\]
A.	\[\frac{(2n)!}{{{(n!)}^{2}}}\]
B.	\[\frac{(2n)!}{(n-1)!(n+1)!}\]
C.	\[\frac{(2n)!}{(n-2)!(n+2)!}\]
D.	none of these
Answer» D. none of these

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If \[{{(1+x)}^{n}}={{C}_{0}}+{{C}_{1}}x+{{C}_{2}}{{x}^{2}}+....+{{C}_{n}}{{x}^{n}},\]then \[{{C}_{0}}{{C}_{2}}+{{C}_{1}}{{C}_{3}}+{{C}_{2}}{{C}_{4}}+...+{{C}_{n-2}}{{C}_{n}}=\]

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