How the Von-Karman momentum integral equation expressed is (\[\theta \] is momentum thickness)?

\[\frac{{{\tau }_{0}}}{\frac{1}{3}\,\rho \,U_{\infty }^{2}}=\frac{\partial \theta }{\partial x}\]

\[\frac{{{\tau }_{0}}}{\frac{1}{2}\,\rho \,U_{\infty }^{2}}=\frac{\partial \theta }{\partial x}\]

\[\frac{{{\tau }_{0}}}{2\,\rho \,U_{\infty }^{2}}=\frac{\partial \theta }{\partial x}\]

Is zero when the circuit contains an ideal inductance only

How the Von-Karman momentum integral equation expressed is (\[\theta \

1.	How the Von-Karman momentum integral equation expressed is (\[\theta \] is momentum thickness)?
A.	\[\frac{{{\tau }_{0}}}{\frac{1}{2}\,\rho \,U_{\infty }^{2}}=\frac{\partial \theta }{\partial x}\]
B.	\[\frac{{{\tau }_{0}}}{2\,\rho \,U_{\infty }^{2}}=\frac{\partial \theta }{\partial x}\]
C.	Is zero when the circuit contains an ideal inductance only
D.	\[\frac{{{\tau }_{0}}}{\frac{1}{3}\,\rho \,U_{\infty }^{2}}=\frac{\partial \theta }{\partial x}\]
Answer» D. \[\frac{{{\tau }_{0}}}{\frac{1}{3}\,\rho \,U_{\infty }^{2}}=\frac{\partial \theta }{\partial x}\]

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How the Von-Karman momentum integral equation expressed is (\[\theta \] is momentum thickness)?

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