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1. |
How many ten-digit numbers can be formed using all the digits of 2435753228 such that odd digits appear only in even places? |
A. | 2! 3! 5! |
B. | (5!)2 |
C. | \(\frac{(5!)^2}{3!}\) |
D. | \(\frac{(5!)^2}{3! (2!)^2}\) |
Answer» E. | |