MCQOPTIONS
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MCQOPTIONS
| 1. |
How is the rate constant ratio kx/kD related to initiator efficiency? |
| A. | k<sub>x</sub>/k<sub>D</sub> = (1-f)/f |
| B. | k<sub>x</sub>/k<sub>D</sub> = f/(1-f) |
| C. | k<sub>x</sub>/k<sub>D</sub> = 1/(1-f) |
| D. | k<sub>x</sub>/k<sub>D</sub> = (1-f)/2f |
| Answer» E. | |