*/*_Heat flow across a hollow sphere of inner radius 'r‚Äö√á√Ö' and outer radius 'r‚Äö√á√á' is directly proportional to?

Question

TuteeHUB · Accepted Answer

(r‚Äö√á√Ö + r‚Äö√á√á)/(r‚Äö√á√Ö . r‚Äö√á√á)

TuteeHUB · Answer

(r‚Äö√á√á - r‚Äö√á√Ö)/(r‚Äö√á√Ö - r‚Äö√á√á)

TuteeHUB · Answer

(r‚Äö√á√á . r‚Äö√á√Ö)/(r‚Äö√á√á - r‚Äö√á√Ö)

TuteeHUB · Answer

(r‚Äö√á√Ö . r‚Äö√á√á)/(r‚Äö√á√Ö + r‚Äö√á√á)

1.	/_Heat flow across a hollow sphere of inner radius 'r‚Äö√á√Ö' and outer radius 'r‚Äö√á√á' is directly proportional to?
A.	(r‚Äö√á√á - r‚Äö√á√Ö)/(r‚Äö√á√Ö - r‚Äö√á√á)
B.	(r‚Äö√á√á . r‚Äö√á√Ö)/(r‚Äö√á√á - r‚Äö√á√Ö)
C.	(r‚Äö√á√Ö + r‚Äö√á√á)/(r‚Äö√á√Ö . r‚Äö√á√á)
D.	(r‚Äö√á√Ö . r‚Äö√á√á)/(r‚Äö√á√Ö + r‚Äö√á√á)
Answer» C. (r‚Äö√á√Ö + r‚Äö√á√á)/(r‚Äö√á√Ö . r‚Äö√á√á)

/_Heat flow across a hollow sphere of inner radius 'r‚Äö√á√Ö' and outer radius 'r‚Äö√á√á' is directly proportional to?