\[{{H}_{2}}O\]is dipolar, whereas \[Be{{F}_{2}}\]is not. It is because [CBSE PMT 1989; 2004]

The electornegativity of F is greater than that of O

\[{{H}_{2}}O\]is linear and \[Be{{F}_{2}}\] is angular

\[{{H}_{2}}O\]is angular and \[Be{{F}_{2}}\] is linear

The electornegativity of F is greater than that of O

\[{{H}_{2}}O\]involves hydrogen bonding whereas \[Be{{F}_{2}}\]is a discrete molecule

\[{{H}_{2}}O\]is dipolar, whereas \[Be{{F}_{2}}\]is not. It is because

1.	\[{{H}_{2}}O\]is dipolar, whereas \[Be{{F}_{2}}\]is not. It is because [CBSE PMT 1989; 2004]
A.	\[{{H}_{2}}O\]is linear and \[Be{{F}_{2}}\] is angular
B.	\[{{H}_{2}}O\]is angular and \[Be{{F}_{2}}\] is linear
C.	The electornegativity of F is greater than that of O
D.	\[{{H}_{2}}O\]involves hydrogen bonding whereas \[Be{{F}_{2}}\]is a discrete molecule
Answer» C. The electornegativity of F is greater than that of O

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\[{{H}_{2}}O\]is dipolar, whereas \[Be{{F}_{2}}\]is not. It is because [CBSE PMT 1989; 2004]

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