\[{{H}_{2}}O\] is dipolar, whereas \[Be{{F}_{2}}\] is not. It I because

The electronegativity of F is greater than that of 0

\[{{H}_{2}}O\] involves hydrogen bonding whereas \[Be{{F}_{2}}\] is a discrete molecule

\[{{H}_{2}}O\] is linear and \[Be{{F}_{2}}\] is angular

\[{{H}_{2}}O\] is angular and \[Be{{F}_{2}}\] is linear

\[{{H}_{2}}O\] is dipolar, whereas \[Be{{F}_{2}}\] is not. It I becaus

1.	\[{{H}_{2}}O\] is dipolar, whereas \[Be{{F}_{2}}\] is not. It I because
A.	The electronegativity of F is greater than that of 0
B.	\[{{H}_{2}}O\] involves hydrogen bonding whereas \[Be{{F}_{2}}\] is a discrete molecule
C.	\[{{H}_{2}}O\] is linear and \[Be{{F}_{2}}\] is angular
D.	\[{{H}_{2}}O\] is angular and \[Be{{F}_{2}}\] is linear
Answer» E.

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\[{{H}_{2}}O\] is dipolar, whereas \[Be{{F}_{2}}\] is not. It I because

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