Given that \[\tan \alpha \] and \[\tan \beta \] are the roots of \[{{x}^{2}}-px+q=0,\] then the value of \[{{\sin }^{2}}(\alpha +\beta )=\][RPET 2000]

\[\frac{{{p}^{2}}}{{{p}^{2}}+{{q}^{2}}}\]

\[\frac{{{p}^{2}}}{{{p}^{2}}+{{(1-q)}^{2}}}\]

\[\frac{{{q}^{2}}}{{{p}^{2}}+{{(1-q)}^{2}}}\]

\[\frac{{{p}^{2}}}{{{(p+q)}^{2}}}\]

Given that \[\tan \alpha \] and \[\tan \beta \] are the roots of \[{{x

1.	Given that \[\tan \alpha \] and \[\tan \beta \] are the roots of \[{{x}^{2}}-px+q=0,\] then the value of \[{{\sin }^{2}}(\alpha +\beta )=\][RPET 2000]
A.	\[\frac{{{p}^{2}}}{{{p}^{2}}+{{(1-q)}^{2}}}\]
B.	\[\frac{{{p}^{2}}}{{{p}^{2}}+{{q}^{2}}}\]
C.	\[\frac{{{q}^{2}}}{{{p}^{2}}+{{(1-q)}^{2}}}\]
D.	\[\frac{{{p}^{2}}}{{{(p+q)}^{2}}}\]
Answer» B. \[\frac{{{p}^{2}}}{{{p}^{2}}+{{q}^{2}}}\]

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Given that \[\tan \alpha \] and \[\tan \beta \] are the roots of \[{{x}^{2}}-px+q=0,\] then the value of \[{{\sin }^{2}}(\alpha +\beta )=\][RPET 2000]

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