1.

Given Reaction Energy Change (in KJ) \[Li\left( s \right)\to Li\left( g \right)\] 161 \[Li\left( g \right)\to L{{i}^{+}}\left( g \right)\] 520 \[\frac{1}{2}{{F}_{2}}(g)\to F(g)\] 77 \[F\left( g \right)+{{e}^{-}}\to {{F}^{-}}\left( g \right)\] Electron gain enthalpy \[L{{i}^{+}}(g)+{{F}^{-}}(g)\to LiF(s)\] -1047 \[Li(s)+\frac{1}{2}{{F}_{2}}(g)\to LiF(s)\] -617 Based on data provided, the value of electron gain enthalpy of fluorine would be:

A. \[-300\,kJ\,mo{{l}^{-1}}\]
B. \[-350kJ\,mo{{l}^{-1}}\]
C. \[-328\text{ }kJ\text{ }mo{{l}^{-1}}\]
D. \[-228\text{ }kJ\text{ }mo{{l}^{-1}}\]
Answer» D. \[-228\text{ }kJ\text{ }mo{{l}^{-1}}\]


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