Given: \[E{{{}^\circ }_{\frac{1}{2}C{{l}_{2}}/C{{l}^{-}}}}=1.36V,\text{ }E{{{}^\circ }_{C{{r}^{3+}}/Cr}}~=-0.74V,\] \[E{{{}^\circ }_{C{{r}_{2}}O_{7}^{2-}/C{{l}^{-}}}}=1.33V,\text{ }E{{{}^\circ }_{MnO_{4}^{-}/M{{n}^{2+}}}}~=1.51\,V\] The correct order of reducing power of the species \[\left( Cr,C{{r}^{3+}},\text{ }M{{n}^{2+}}and\text{ }C{{l}^{-}} \right)\] will be:

• A. \[M{{n}^{2+}}<C{{l}^{-}}<C{{r}^{3+}}<Cr\]
• B. \[M{{n}^{2+}}<C{{r}^{3+}}<C{{l}^{-}}<Cr\]
• C. \[C{{r}^{3+}}<C{{l}^{-}}<M{{n}^{2+}}<Cr\]
• D. \[C{{r}^{3+}}<C{{l}^{-}}<Cr<M{{n}^{2+}}\]