1.

Given a Fourier transform pair x(t) ↔ X(jω) = \(\frac{2 sin⁡ω}{ω}\), where, x(t) = 1 for |t|<1 and 0, otherwise. Then the Fourier transform of y(t) having the shape of a triangular waveform from t=-2 to t=2 and maximum peak value=2 is ___________

A. \(\frac{4 sin^2 ω}{ω^2}\)
B. \(\frac{2 sin^2 ω}{πω^2}\)
C. \(\frac{8π sin^2 ω}{ω^2}\)
D. \(\frac{8 sin^2 ω}{ω^2}\)
Answer» B. \(\frac{2 sin^2 ω}{πω^2}\)


Discussion

No Comment Found