Given \[a+d>b+c\] where \[a,\ b,\ c,\ d\] are real numbers, then [Kurukshetra CEE 1998]

\[(a+b),\ (b+c),\ (c+d),\ (a+d)\]are in A.P.

\[\frac{1}{a},\ \frac{1}{b},\ \frac{1}{c},\ \frac{1}{d}\] are in A.P.

\[\frac{1}{a+b},\ \frac{1}{b+c},\ \frac{1}{c+d},\ \frac{1}{a+d}\] are in A.P.

Given \[a+d>b+c\] where \[a,\ b,\ c,\ d\] are real numbers, then [Kuru

1.	Given \[a+d>b+c\] where \[a,\ b,\ c,\ d\] are real numbers, then [Kurukshetra CEE 1998]
A.	\[a,\ b,\ c,\ d\] are in A.P.
B.	\[\frac{1}{a},\ \frac{1}{b},\ \frac{1}{c},\ \frac{1}{d}\] are in A.P.
C.	\[(a+b),\ (b+c),\ (c+d),\ (a+d)\]are in A.P.
D.	\[\frac{1}{a+b},\ \frac{1}{b+c},\ \frac{1}{c+d},\ \frac{1}{a+d}\] are in A.P.
Answer» C. \[(a+b),\ (b+c),\ (c+d),\ (a+d)\]are in A.P.

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Given \[a+d>b+c\] where \[a,\ b,\ c,\ d\] are real numbers, then [Kurukshetra CEE 1998]

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