Given a continuous time signal s(t) = 5cos(200 πt). The minimum sampl – McqOptions

MCQOPTIONS

1.	Given a continuous time signal s(t) = 5cos(200 πt). The minimum sampling rate required to avoid aliasing will be
A.	50 Hz
B.	100 Hz
C.	200 Hz
D.	400 Hz
Answer» D. 400 Hz

Discussion

No Comment Found

Related MCQs

The loss in weight should not exceed ________ % when tested with Na2SO4 and ________ % with MgSO4 solution.
The mineral oil if present in mixing for concrete ______________
When sand is fully dry then it’s volume is _________
Loss on Ignition (L.O.I.) is the loss in weight of cement after being heated to ____________
Find the Nyquist rate and Nyquist interval for the signal f(t) = -10 sin ⁡40πt cos ⁡300πt.
Determine the Nyquist rate of the signal x(t) = 1 + cos⁡ 2000πt + sin⁡ 4000πt.
The sampling frequency of a signal is Fs = 2000 samples per second. Find its Nyquist interval.
Find the Nyquist rate and Nyquist interval for the signal f(t) = rect(200t).
Find the Nyquist rate and Nyquist interval for the signal f(t) = 1 + sinc300πt.
Find the Nyquist rate and Nyquist interval for the signal f(t)=\(\frac{sin⁡500πt}{πt}\).