Ge(II)compounds are powerful reducing agents whereas Pb(IV)compounds are strong oxidants. It is because

Pb is more electropositive than Ge

ionization potential of lead is less than that of Ge

ionic radii of \[P{{b}^{2+}}\]and \[P{{b}^{4+}}\] are larger than those of \[G{{e}^{2+}}\] and \[G{{e}^{4+}}\]

of more pronounced inert pair effect in lead than in Ge

Ge(II)compounds are powerful reducing agents whereas Pb(IV)compounds a

1.	Ge(II)compounds are powerful reducing agents whereas Pb(IV)compounds are strong oxidants. It is because
A.	Pb is more electropositive than Ge
B.	ionization potential of lead is less than that of Ge
C.	ionic radii of \[P{{b}^{2+}}\]and \[P{{b}^{4+}}\] are larger than those of \[G{{e}^{2+}}\] and \[G{{e}^{4+}}\]
D.	of more pronounced inert pair effect in lead than in Ge
Answer» E.

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Ge(II)compounds are powerful reducing agents whereas Pb(IV)compounds are strong oxidants. It is because

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