Function \[y={{\sin }^{-1}}\left( \frac{2x}{1+{{x}^{2}}} \right)\] is not differentiable for [IIT Screening]

Function \[y={{\sin }^{-1}}\left( \frac{2x}{1+{{x}^{2}}} \right)\] is

1.	Function \[y={{\sin }^{-1}}\left( \frac{2x}{1+{{x}^{2}}} \right)\] is not differentiable for [IIT Screening]
A.	\[\|x\|\,<1\]
B.	\[x=1,-1\]
C.	\[\|x\|\,>1\]
D.	None of these
Answer» C. \[\|x\|\,>1\]

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Function \[y={{\sin }^{-1}}\left( \frac{2x}{1+{{x}^{2}}} \right)\] is not differentiable for [IIT Screening]

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