1.

Function \[f(x)=\frac{1-\cos 4x}{8{{x}^{2}}},\] where \[x\ne 0\]and \[f(x)=k\] where \[x=0\] is a continous function at \[x=0\]then the value of k will be [AMU 2005]

A.            \[k=0\]
B.            \[k=1\]
C.            \[k=-1\]
D.            None of these
Answer» C.            \[k=-1\]


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