1.

From the top of a tower, a particle is thrown vertically downwards with a velocity of 10 m/s. The ratio of the distances, covered by it in the 3rd and 2nd seconds of the motion is (Take \[g=10m/{{s}^{2}}\])                             [AIIMS 2000; CBSE PMT 2002]

A.             5 : 7    
B.             7 : 5
C.             3 : 6    
D.             6 : 3
Answer» C.             3 : 6    


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