MCQOPTIONS
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MCQOPTIONS
| 1. |
From the figure, obtain state equation |
| A. | \(\left[ {\dot X} \right] = \left[ {\begin{array}{*{20}{c}} 0&{ - 3}\\ { - 2}&4 \end{array}} \right]\left[ X \right] + \left[ {\begin{array}{*{20}{c}} 0\\ 1 \end{array}} \right]u\) |
| B. | \(\left[ {\dot X} \right] = \left[ {\begin{array}{*{20}{c}} -2&{ 4}\\ { 0}&-3 \end{array}} \right]\left[ X \right] + \left[ {\begin{array}{*{20}{c}} 0\\ 1 \end{array}} \right]u\) |
| C. | \(\left[ {\dot X} \right] = \left[ {\begin{array}{*{20}{c}} 0&{ - 3}\\ { - 2}&4 \end{array}} \right]\left[ X \right] + \left[ {\begin{array}{*{20}{c}} 1\\ 0 \end{array}} \right]u\) |
| D. | \(\left[ {\dot X} \right] = \left[ {\begin{array}{*{20}{c}} -2&{ 4}\\ { 0}&-3 \end{array}} \right]\left[ X \right] + \left[ {\begin{array}{*{20}{c}} 1\\ 0 \end{array}} \right]u\) |
| Answer» C. \(\left[ {\dot X} \right] = \left[ {\begin{array}{*{20}{c}} 0&{ - 3}\\ { - 2}&4 \end{array}} \right]\left[ X \right] + \left[ {\begin{array}{*{20}{c}} 1\\ 0 \end{array}} \right]u\) | |