\(\frac{{{x^2}{{\left( {x - 4} \right)}^2}}}{{{{\left( {x\; + \;4} \right)}^2} - 4x}} \div \frac{{{{\left( {{x^2} - 4x} \right)}^3}}}{{{{\left( {x\; + \;4} \right)}^2}}}\; \times \;\frac{{64 - {x^3}}}{{16 - {x^2}}}\) is equal to

• A. \(\frac{{x - 4}}{{x\; + \;4}}\)
• B. \(\frac{{x\; + \;4}}{{x\left( {4 - x} \right)}}\)
• C. \(\frac{{x\; + \;4}}{{x\left( {x - 4} \right)}}\)
• D. \(\frac{{x\; + \;4}}{{x - 4}}\)