$$\frac{1}{2}\left( {\log x + \log y} \right)$$will equal to $$\log \left( {\frac{{x + y}}{2}} \right)$$if -

$$\frac{1}{2}\left( {\log x + \log y} \right)$$will equal to $$\log \l

1.	$$\frac{1}{2}\left( {\log x + \log y} \right)$$will equal to $$\log \left( {\frac{{x + y}}{2}} \right)$$if -
A.	= 0
B.	= $$\sqrt {\text{y}} $$
C.	= y
D.	= $$\frac{{\text{y}}}{2}$$
Answer» D. = $$\frac{{\text{y}}}{2}$$