\[\frac{\sin \theta }{1-\cot \theta }+\frac{\cos \theta }{1-\tan \theta }=\] [Karnataka CET 1998]

\[\frac{\sin \theta }{1-\cot \theta }+\frac{\cos \theta }{1-\tan \thet

1.	\[\frac{\sin \theta }{1-\cot \theta }+\frac{\cos \theta }{1-\tan \theta }=\] [Karnataka CET 1998]
A.	0
B.	1
C.	\[\cos \theta -\sin \theta \]
D.	\[\cos \theta +\sin \theta \]
Answer» E.

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\[\frac{\sin \theta }{1-\cot \theta }+\frac{\cos \theta }{1-\tan \theta }=\] [Karnataka CET 1998]

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