\[\frac{\sin 2A}{1+\cos 2A}.\frac{\cos A}{1+\cos A}=\]

1.	\[\frac{\sin 2A}{1+\cos 2A}.\frac{\cos A}{1+\cos A}=\]
A.	\[\tan \frac{A}{2}\]
B.	\[\cot \frac{A}{2}\]
C.	\[\sec \frac{A}{2}\]
D.	\[\text{cosec}\frac{A}{2}\]
Answer» B. \[\cot \frac{A}{2}\]

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\[\frac{\sin 2A}{1+\cos 2A}.\frac{\cos A}{1+\cos A}=\]

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