\[\frac{{{d}^{n}}}{d{{x}^{n}}}({{e}^{2x}}+{{e}^{-2x}})=\]

1.	\[\frac{{{d}^{n}}}{d{{x}^{n}}}({{e}^{2x}}+{{e}^{-2x}})=\]
A.	\[{{e}^{2x}}+{{(-1)}^{n}}{{e}^{-2x}}\]
B.	\[{{2}^{n}}({{e}^{2x}}-{{e}^{-2x}})\]
C.	\[{{2}^{n}}[{{e}^{2x}}+{{(-1)}^{n}}{{e}^{-2x}}]\]
D.	None of these
Answer» D. None of these

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\[\frac{{{d}^{n}}}{d{{x}^{n}}}({{e}^{2x}}+{{e}^{-2x}})=\]

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