\[\frac{d}{dx}{{\tan }^{-1}}\left[ \frac{3{{a}^{2}}x-{{x}^{3}}}{a({{a}^{2}}-3{{x}^{2}})} \right]\]at \[x=0\]is

\[\frac{d}{dx}{{\tan }^{-1}}\left[ \frac{3{{a}^{2}}x-{{x}^{3}}}{a({{a}

1.	\[\frac{d}{dx}{{\tan }^{-1}}\left[ \frac{3{{a}^{2}}x-{{x}^{3}}}{a({{a}^{2}}-3{{x}^{2}})} \right]\]at \[x=0\]is
A.	\[\frac{1}{a}\]
B.	\[\frac{3}{a}\]
C.	\[3a\]
D.	3
Answer» C. \[3a\]

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\[\frac{d}{dx}{{\tan }^{-1}}\left[ \frac{3{{a}^{2}}x-{{x}^{3}}}{a({{a}^{2}}-3{{x}^{2}})} \right]\]at \[x=0\]is

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