\[\frac{d}{dx}{{\tan }^{-1}}\frac{x}{\sqrt{{{a}^{2}}-{{x}^{2}}}}=\]

1.	\[\frac{d}{dx}{{\tan }^{-1}}\frac{x}{\sqrt{{{a}^{2}}-{{x}^{2}}}}=\]
A.	\[\frac{a}{{{a}^{2}}+{{x}^{2}}}\]
B.	\[\frac{-a}{{{a}^{2}}+{{x}^{2}}}\]
C.	\[\frac{1}{a\sqrt{{{a}^{2}}-{{x}^{2}}}}\]
D.	\[\frac{1}{\sqrt{{{a}^{2}}-{{x}^{2}}}}\]
Answer» E.

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\[\frac{d}{dx}{{\tan }^{-1}}\frac{x}{\sqrt{{{a}^{2}}-{{x}^{2}}}}=\]

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