\[\frac{d}{dx}{{\tan }^{-1}}\frac{4\sqrt{x}}{1-4x}=\]

1.	\[\frac{d}{dx}{{\tan }^{-1}}\frac{4\sqrt{x}}{1-4x}=\]
A.	\[\frac{1}{\sqrt{x}(1+4x)}\]
B.	\[\frac{2}{\sqrt{x}(1+4x)}\]
C.	\[\frac{4}{\sqrt{x}(1+4x)}\]
D.	None of these
Answer» C. \[\frac{4}{\sqrt{x}(1+4x)}\]

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\[\frac{d}{dx}{{\tan }^{-1}}\frac{4\sqrt{x}}{1-4x}=\]

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