\[\frac{d}{dx}\sqrt{\frac{1-\sin 2x}{1+\sin 2x}}=\] [AISSE 1985; DSSE 1986]

\[{{\sec }^{2}}\left( \frac{\pi }{4}+x \right)\]

\[-{{\sec }^{2}}\left( \frac{\pi }{4}-x \right)\]

\[{{\sec }^{2}}\left( \frac{\pi }{4}-x \right)\]

\[\frac{d}{dx}\sqrt{\frac{1-\sin 2x}{1+\sin 2x}}=\] [AISSE 1985

1.	\[\frac{d}{dx}\sqrt{\frac{1-\sin 2x}{1+\sin 2x}}=\] [AISSE 1985; DSSE 1986]
A.	\[{{\sec }^{2}}x\]
B.	\[-{{\sec }^{2}}\left( \frac{\pi }{4}-x \right)\]
C.	\[{{\sec }^{2}}\left( \frac{\pi }{4}+x \right)\]
D.	\[{{\sec }^{2}}\left( \frac{\pi }{4}-x \right)\]
Answer» C. \[{{\sec }^{2}}\left( \frac{\pi }{4}+x \right)\]

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\[\frac{d}{dx}\sqrt{\frac{1-\sin 2x}{1+\sin 2x}}=\] [AISSE 1985; DSSE 1986]

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