\[\frac{d}{dx}\sqrt{\frac{1+\cos 2x}{1-\cos 2x}}=\]

1.	\[\frac{d}{dx}\sqrt{\frac{1+\cos 2x}{1-\cos 2x}}=\]
A.	\[{{\sec }^{2}}x\]
B.	\[-\text{cose}{{\text{c}}^{2}}x\]
C.	\[2\,{{\sec }^{2}}\frac{x}{2}\]
D.	\[-2\text{cose}{{\text{c}}^{2}}\frac{x}{2}\]
Answer» C. \[2\,{{\sec }^{2}}\frac{x}{2}\]

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\[\frac{d}{dx}\sqrt{\frac{1+\cos 2x}{1-\cos 2x}}=\]

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