\[\frac{d}{dx}(\sin 2{{x}^{2}})\] equals [RPET 1996]

\[2\sin {{x}^{2}}\cos {{x}^{2}}\]

\[4x\sin ({{x}^{2}})\cos ({{x}^{2}})\]

\[\frac{d}{dx}(\sin 2{{x}^{2}})\] equals �

1.	\[\frac{d}{dx}(\sin 2{{x}^{2}})\] equals [RPET 1996]
A.	\[4x\cos \,(2{{x}^{2}})\]
B.	\[2\sin {{x}^{2}}\cos {{x}^{2}}\]
C.	\[4x\sin ({{x}^{2}})\]
D.	\[4x\sin ({{x}^{2}})\cos ({{x}^{2}})\]
Answer» B. \[2\sin {{x}^{2}}\cos {{x}^{2}}\]

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\[\frac{d}{dx}(\sin 2{{x}^{2}})\] equals [RPET 1996]

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