\[\frac{d}{dx}{{\sin }^{-1}}(2ax\sqrt{1-{{a}^{2}}{{x}^{2}}})=\]

1.	\[\frac{d}{dx}{{\sin }^{-1}}(2ax\sqrt{1-{{a}^{2}}{{x}^{2}}})=\]
A.	\[\frac{2a}{\sqrt{{{a}^{2}}-{{x}^{2}}}}\]
B.	\[\frac{a}{\sqrt{{{a}^{2}}-{{x}^{2}}}}\]
C.	\[\frac{2a}{\sqrt{1-{{a}^{2}}{{x}^{2}}}}\]
D.	\[\frac{a}{\sqrt{1-{{a}^{2}}{{x}^{2}}}}\]
Answer» D. \[\frac{a}{\sqrt{1-{{a}^{2}}{{x}^{2}}}}\]

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\[\frac{d}{dx}{{\sin }^{-1}}(2ax\sqrt{1-{{a}^{2}}{{x}^{2}}})=\]

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