\[\frac{d}{dx}{{\log }_{\sqrt{x}}}(1/x)\]is equal to [AMU 1999]

\[-\frac{1}{{{x}^{2}}\sqrt{x}}\]

\[\frac{d}{dx}{{\log }_{\sqrt{x}}}(1/x)\]is equal to �

1.	\[\frac{d}{dx}{{\log }_{\sqrt{x}}}(1/x)\]is equal to [AMU 1999]
A.	\[-\frac{1}{2\sqrt{x}}\]
B.	? 2
C.	\[-\frac{1}{{{x}^{2}}\sqrt{x}}\]
D.	0
Answer» E.

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\[\frac{d}{dx}{{\log }_{\sqrt{x}}}(1/x)\]is equal to [AMU 1999]

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