\[\frac{d}{dx}\left[ {{\sin }^{2}}{{\cot }^{-1}}\left\{ \sqrt{\frac{1-x}{1+x}} \right\} \right]\] equals [MP PET 2002]

\[\frac{d}{dx}\left[ {{\sin }^{2}}{{\cot }^{-1}}\left\{ \sqrt{\frac{1-

1.	\[\frac{d}{dx}\left[ {{\sin }^{2}}{{\cot }^{-1}}\left\{ \sqrt{\frac{1-x}{1+x}} \right\} \right]\] equals [MP PET 2002]
A.	\[-1\]
B.	\[\frac{1}{2}\]
C.	\[-\frac{1}{2}\]
D.	1
Answer» C. \[-\frac{1}{2}\]

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\[\frac{d}{dx}\left[ {{\sin }^{2}}{{\cot }^{-1}}\left\{ \sqrt{\frac{1-x}{1+x}} \right\} \right]\] equals [MP PET 2002]

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