\[\frac{d}{dx}\left( \frac{{{\cot }^{2}}x-1}{{{\cot }^{2}}x+1} \right)

1.	\[\frac{d}{dx}\left( \frac{{{\cot }^{2}}x-1}{{{\cot }^{2}}x+1} \right)=\]
A.	\[-\sin 2x\]
B.	\[2\sin 2x\]
C.	\[2\cos 2x\]
D.	\[-2\sin 2x\]
Answer» E.

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\[\frac{d}{dx}\left( \frac{{{\cot }^{2}}x-1}{{{\cot }^{2}}x+1} \right)=\]

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