\[\frac{d}{dx}[\cos {{(1-{{x}^{2}})}^{2}}]\]= [AISSE 1981; AI CBSE 1979]

\[-2(1-{{x}^{2}})\sin {{(1-{{x}^{2}})}^{2}}\]

\[-2x(1-{{x}^{2}})\sin {{(1-{{x}^{2}})}^{2}}\]

\[-4x(1-{{x}^{2}})\sin {{(1-{{x}^{2}})}^{2}}\]

\[4x(1-{{x}^{2}})\sin {{(1-{{x}^{2}})}^{2}}\]

\[\frac{d}{dx}[\cos {{(1-{{x}^{2}})}^{2}}]\]= �

1.	\[\frac{d}{dx}[\cos {{(1-{{x}^{2}})}^{2}}]\]= [AISSE 1981; AI CBSE 1979]
A.	\[-2x(1-{{x}^{2}})\sin {{(1-{{x}^{2}})}^{2}}\]
B.	\[-4x(1-{{x}^{2}})\sin {{(1-{{x}^{2}})}^{2}}\]
C.	\[4x(1-{{x}^{2}})\sin {{(1-{{x}^{2}})}^{2}}\]
D.	\[-2(1-{{x}^{2}})\sin {{(1-{{x}^{2}})}^{2}}\]
Answer» D. \[-2(1-{{x}^{2}})\sin {{(1-{{x}^{2}})}^{2}}\]

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\[\frac{d}{dx}[\cos {{(1-{{x}^{2}})}^{2}}]\]= [AISSE 1981; AI CBSE 1979]

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