\[\frac{d}{dx}{{\cos }^{-1}}\sqrt{\frac{1+{{x}^{2}}}{2}}=\] [AI CBSE 1988]

\[\frac{x}{\sqrt{1-{{x}^{4}}}}\]

\[\frac{-1}{2\sqrt{1-{{x}^{4}}}}\]

\[\frac{1}{2\sqrt{1-{{x}^{4}}}}\]

\[\frac{-x}{\sqrt{1-{{x}^{4}}}}\]

\[\frac{d}{dx}{{\cos }^{-1}}\sqrt{\frac{1+{{x}^{2}}}{2}}=\] �

1.	\[\frac{d}{dx}{{\cos }^{-1}}\sqrt{\frac{1+{{x}^{2}}}{2}}=\] [AI CBSE 1988]
A.	\[\frac{-1}{2\sqrt{1-{{x}^{4}}}}\]
B.	\[\frac{1}{2\sqrt{1-{{x}^{4}}}}\]
C.	\[\frac{-x}{\sqrt{1-{{x}^{4}}}}\]
D.	\[\frac{x}{\sqrt{1-{{x}^{4}}}}\]
Answer» D. \[\frac{x}{\sqrt{1-{{x}^{4}}}}\]

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\[\frac{d}{dx}{{\cos }^{-1}}\sqrt{\frac{1+{{x}^{2}}}{2}}=\] [AI CBSE 1988]

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