1.

\[\frac{{{d}^{2}}x}{d{{y}^{2}}}\] is equal to [AMU 2001]

A.            \[\frac{1}{{{(dy/dx)}^{2}}}\]
B.            \[\frac{\left( {{d}^{2}}y/d{{x}^{2}} \right)}{{{\left( dy/dx \right)}^{2}}}\]
C.            \[\frac{{{d}^{2}}y}{d{{x}^{2}}}\]
D.            \[\frac{\left( -{{d}^{2}}y/d{{x}^{2}} \right)}{{{\left( dy/dx \right)}^{2}}}\]
Answer» E.


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