\[\frac{\cos {{10}^{o}}+\sin {{10}^{o}}}{\cos {{10}^{o}}-\sin {{10}^{o}}}=\] [MP PET 2002]

\[\frac{\cos {{10}^{o}}+\sin {{10}^{o}}}{\cos {{10}^{o}}-\sin {{10}^{o

1.	\[\frac{\cos {{10}^{o}}+\sin {{10}^{o}}}{\cos {{10}^{o}}-\sin {{10}^{o}}}=\] [MP PET 2002]
A.	\[\tan \,{{55}^{o}}\]
B.	\[\cot {{55}^{o}}\]
C.	\[-\tan {{35}^{o}}\]
D.	\[-\cot {{35}^{o}}\]
Answer» B. \[\cot {{55}^{o}}\]

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\[\frac{\cos {{10}^{o}}+\sin {{10}^{o}}}{\cos {{10}^{o}}-\sin {{10}^{o}}}=\] [MP PET 2002]

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