\[\frac{2\sin \theta \,\tan \theta (1-\tan \theta )+2\sin \theta {{\sec }^{2}}\theta }{{{(1+\tan \theta )}^{2}}}=\] [Roorkee 1975]

\[\frac{2\sin \theta }{{{(1+\tan \theta )}^{2}}}\]

\[\frac{\sin \,\theta }{1+\tan \theta }\]

\[\frac{2\,\sin \theta }{1+\tan \theta }\]

\[\frac{2\sin \theta \,\tan \theta (1-\tan \theta )+2\sin \theta {{\se

1.	\[\frac{2\sin \theta \,\tan \theta (1-\tan \theta )+2\sin \theta {{\sec }^{2}}\theta }{{{(1+\tan \theta )}^{2}}}=\] [Roorkee 1975]
A.	\[\frac{\sin \,\theta }{1+\tan \theta }\]
B.	\[\frac{2\,\sin \theta }{1+\tan \theta }\]
C.	\[\frac{2\sin \theta }{{{(1+\tan \theta )}^{2}}}\]
D.	None of these
Answer» C. \[\frac{2\sin \theta }{{{(1+\tan \theta )}^{2}}}\]

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\[\frac{2\sin \theta \,\tan \theta (1-\tan \theta )+2\sin \theta {{\sec }^{2}}\theta }{{{(1+\tan \theta )}^{2}}}=\] [Roorkee 1975]

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