\[\frac{1}{2}{{\cos }^{-1}}\left( \frac{1-x}{1+x} \right)=\]

1.	\[\frac{1}{2}{{\cos }^{-1}}\left( \frac{1-x}{1+x} \right)=\]
A.	\[{{\cot }^{-1}}\sqrt{x}\]
B.	\[{{\tan }^{-1}}\sqrt{x}\]
C.	\[{{\tan }^{-1}}x\]
D.	\[{{\cot }^{-1}}x\]
Answer» C. \[{{\tan }^{-1}}x\]

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\[\frac{1}{2}{{\cos }^{-1}}\left( \frac{1-x}{1+x} \right)=\]

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