\[\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+....+\frac{1}{n(n+1)}\] equals

\[\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+....+\frac{1}{n(n+1)}\] eq

1.	\[\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+....+\frac{1}{n(n+1)}\] equals
A.	\[\frac{1}{n(n+1)}\]
B.	\[\frac{n}{n+1}\]
C.	\[\frac{2n}{n+1}\]
D.	\[\frac{2}{n(n+1)}\]
Answer» C. \[\frac{2n}{n+1}\]

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\[\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+....+\frac{1}{n(n+1)}\] equals

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