Four plates of the same area of cross-section are joined as shown in the figure. The distance between each plate is\[d\]. The equivalent capacity across A and B will be

• A.            \[\frac{2{{\varepsilon }_{0}}A}{d}\]
• B.                    \[\frac{3{{\varepsilon }_{0}}A}{d}\]
• C.                    \[\frac{3{{\varepsilon }_{0}}A}{2d}\]
• D.                    \[\frac{{{\varepsilon }_{0}}A}{d}\]