Formation of a solution from two components can be considered as (i) Pure solvent $$\to $$ separated solvent molecules, $$\Delta {{H}_{1}}$$ (ii) Pure solute $$\to $$ separated solute molecules, $$\Delta {{H}_{2}}$$ (iii) Separated solvent & solute molecules $$\to $$ Solution, $$\Delta {{H}_{3}}$$ solution so formed will be ideal if

Question

TuteeHUB · Accepted Answer

$$\Delta {{H}_{so\ln }}=\Delta {{H}_{1}}+\Delta {{H}_{2}}-\Delta {{H}_{3}}$$

TuteeHUB · Answer

$$\Delta {{H}_{so\ln }}=\Delta {{H}_{3}}-\Delta {{H}_{1}}-\Delta {{H}_{2}}$$

TuteeHUB · Answer

$$\Delta {{H}_{so\ln }}=\Delta {{H}_{1}}+\Delta {{H}_{2}}+\Delta {{H}_{3}}$$

TuteeHUB · Answer

$$\Delta {{H}_{so\ln }}=\Delta {{H}_{1}}-\Delta {{H}_{2}}-\Delta {{H}_{3}}$$

1.	Formation of a solution from two components can be considered as (i) Pure solvent \[\to \] separated solvent molecules, \[\Delta {{H}_{1}}\] (ii) Pure solute \[\to \] separated solute molecules, \[\Delta {{H}_{2}}\] (iii) Separated solvent & solute molecules \[\to \] Solution, \[\Delta {{H}_{3}}\] solution so formed will be ideal if
A.	\[\Delta {{H}_{so\ln }}=\Delta {{H}_{3}}-\Delta {{H}_{1}}-\Delta {{H}_{2}}\]
B.	\[\Delta {{H}_{so\ln }}=\Delta {{H}_{1}}+\Delta {{H}_{2}}+\Delta {{H}_{3}}\]
C.	\[\Delta {{H}_{so\ln }}=\Delta {{H}_{1}}+\Delta {{H}_{2}}-\Delta {{H}_{3}}\]
D.	\[\Delta {{H}_{so\ln }}=\Delta {{H}_{1}}-\Delta {{H}_{2}}-\Delta {{H}_{3}}\]
Answer» C. \[\Delta {{H}_{so\ln }}=\Delta {{H}_{1}}+\Delta {{H}_{2}}-\Delta {{H}_{3}}\]

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