Force between two identical charges placed at a distance of r in vacuu – McqOptions

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1.	Force between two identical charges placed at a distance of r in vacuum is F, Now a slab of dielectric of dielectric contrant 4 is inserted between these two charges. If the thickness of the slab is r/2, then the force between the charges will become
A.	F
B.	\[\frac{3}{5}F\]
C.	\[\frac{4}{9}F\]
D.	\[\frac{F}{2}\]
Answer» D. \[\frac{F}{2}\]

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