For the reversible reaction, $${{N}_{2(g)}}+3{{H}_{2(g)}}$$ ⇌$$2N{{H}_{3(g)}}$$ at 500°C, the value of $${{K}_{P}}$$ is $$1.44\times {{10}^{-5}}$$ when partial pressure is measured in atmospheres. The corresponding value of $${{K}_{c}}$$ with concentration in mole litre-1, is [IIT Screening 2000; Pb. CET 2004]

Question

For the reversible reaction, $${{N}_{2(g)}}+3{{H}_{2(g)}}$$ ⇌$$2N{{H}_{3(g)}}$$ at 500°C, the value of $${{K}_{P}}$$ is $$1.44\times {{10}^{-5}}$$ when partial pressure is measured in atmospheres. The corresponding value of $${{K}_{c}}$$ with concentration in mole litre-1, is [IIT Screening 2000; Pb. CET  2004]

TuteeHUB · Accepted Answer

NA

TuteeHUB · Answer

$$1.44\times {{10}^{-5}}$$/$${{\left( 0.082\times 500 \right)}^{-2}}$$

TuteeHUB · Answer

$$1.44\times {{10}^{-5}}$$/$${{\left( 8.314\times 773 \right)}^{-2}}$$

TuteeHUB · Answer

$$1.44\times {{10}^{-5}}$$/$${{\left( 0.082\times 773 \right)}^{2}}$$

TuteeHUB · Answer

$$1.44\times {{10}^{-5}}$$/$${{\left( 0.082\times 773 \right)}^{-2}}$$

1.	For the reversible reaction, \[{{N}_{2(g)}}+3{{H}_{2(g)}}\] ⇌\[2N{{H}_{3(g)}}\] at 500°C, the value of \[{{K}_{P}}\] is \[1.44\times {{10}^{-5}}\] when partial pressure is measured in atmospheres. The corresponding value of \[{{K}_{c}}\] with concentration in mole litre-1, is [IIT Screening 2000; Pb. CET 2004]
A.	\[1.44\times {{10}^{-5}}\]/\[{{\left( 0.082\times 500 \right)}^{-2}}\]
B.	\[1.44\times {{10}^{-5}}\]/\[{{\left( 8.314\times 773 \right)}^{-2}}\]
C.	\[1.44\times {{10}^{-5}}\]/\[{{\left( 0.082\times 773 \right)}^{2}}\]
D.	\[1.44\times {{10}^{-5}}\]/\[{{\left( 0.082\times 773 \right)}^{-2}}\]
Answer» E.

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